40b^2=160

Solution for 40b^2=160 equation:

40b^2=160

We move all terms to the left:

40b^2-(160)=0

a = 40; b = 0; c = -160;
Δ = b2-4ac
Δ = 02-4·40·(-160)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*40}=\frac{-160}{80}
=-2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*40}=\frac{160}{80}
=2
$